- Identify the known oxidation states: Hydrogen (H) usually has an oxidation state of +1.
- Determine the total contribution from hydrogen: In PH3, there are three hydrogen atoms, so their total contribution is 3 * (+1) = +3.
- Set up the equation: Let x be the oxidation state of phosphorus (P). The sum of the oxidation states in a neutral molecule must be zero. Therefore, x + (+3) = 0.
- Solve for x: Solving the equation x + 3 = 0 gives x = -3.
- Conclusion: The oxidation state of phosphorus in PH3 is -3.
- What is the oxidation state of nitrogen in NH3?
- What is the oxidation state of sulfur in H2SO4?
- What is the oxidation state of chromium in K2Cr2O7?
- -3
- +6
- +6
Hey guys! Ever wondered about the oxidation state of phosphorus in PH3? It might seem a bit complex at first, but trust me, it's actually pretty straightforward once you grasp the basic principles. So, let's dive right in and break it down in a way that’s super easy to understand. We'll cover the fundamentals of oxidation states, how to apply them to molecules, and specifically how to figure out the oxidation state of phosphorus in phosphine (PH3). By the end of this article, you’ll be a pro at determining oxidation states, and PH3 will be a piece of cake!
Understanding Oxidation States
First off, what exactly are oxidation states? Think of them as a way to keep track of how electrons are distributed in a molecule. They aren't actual charges, but rather hypothetical charges that atoms would have if all bonds were completely ionic. Oxidation states help us understand and predict how different elements will behave in chemical reactions. Oxidation states, also known as oxidation numbers, are crucial for balancing redox reactions and understanding the electron transfer processes involved. Remember, assigning oxidation states is based on a set of rules, and the goal is to follow these rules consistently to accurately determine the oxidation state of each element in a compound.
To really nail this, let’s walk through the basic rules for assigning oxidation states. These rules are your best friends when you're trying to figure out the oxidation state of an element in any compound. First, the oxidation state of an atom in its elemental form is always 0. For example, in a piece of pure sodium (Na) or a diatomic molecule like oxygen (O2), the oxidation state of each atom is 0. Next, the oxidation state of a monoatomic ion is the same as its charge. So, for sodium ion (Na+), the oxidation state is +1, and for chloride ion (Cl-), it’s -1. This makes sense because these ions have either lost or gained electrons to achieve a stable electron configuration. When dealing with compounds, there are a few elements that almost always have the same oxidation state. Oxygen, for instance, usually has an oxidation state of -2, except in a few cases like peroxides (where it's -1) or when combined with fluorine (where it can be positive). Hydrogen usually has an oxidation state of +1, except when it's bonded to a metal in a metal hydride (like NaH), where it's -1. Fluorine always has an oxidation state of -1 in compounds. Finally, the sum of the oxidation states of all atoms in a neutral molecule must be zero, and the sum of the oxidation states in a polyatomic ion must equal the charge of the ion. By following these rules, you can systematically determine the oxidation states of elements in various compounds and ions.
Applying the Rules to PH3
Now, let’s get to the heart of the matter: finding the oxidation state of phosphorus in PH3 (phosphine). Phosphine is a simple molecule consisting of one phosphorus atom and three hydrogen atoms. To determine the oxidation state of phosphorus, we need to apply the rules we just discussed.
First, remember that hydrogen typically has an oxidation state of +1. Since there are three hydrogen atoms in PH3, the total positive charge from the hydrogen atoms is +3. Now, here’s the key: the molecule PH3 is neutral, meaning it has no overall charge. Therefore, the sum of the oxidation states of all the atoms in the molecule must be zero. If the three hydrogen atoms contribute a total of +3, the phosphorus atom must contribute a charge that balances this out to reach zero. So, the oxidation state of phosphorus in PH3 must be -3. This is because -3 (from phosphorus) + 3 (from the three hydrogens) = 0. And there you have it! The oxidation state of phosphorus in PH3 is -3. Understanding how to apply these rules step by step makes it much easier to tackle more complex molecules in the future. Keep practicing, and you’ll become a pro at determining oxidation states in no time!
Step-by-Step Calculation
Let's break down the calculation step-by-step to make sure it's crystal clear.
Why is Phosphorus -3 in PH3?
You might be wondering why phosphorus has a negative oxidation state in PH3. This is because phosphorus is more electronegative than hydrogen. Electronegativity is a measure of an atom's ability to attract electrons in a chemical bond. When phosphorus bonds with hydrogen, it pulls the electron density towards itself, effectively gaining electrons compared to its neutral state. This gain of electron density is what gives phosphorus its negative oxidation state.
In simple terms, phosphorus hogs the electrons more than hydrogen does. Because phosphorus is more electronegative, it is assigned a negative oxidation state, indicating that it has gained electron density. The three hydrogen atoms, each with an oxidation state of +1, balance out this negative charge, resulting in a neutral molecule. This concept of electronegativity helps explain why certain elements tend to have positive or negative oxidation states in compounds. Elements with higher electronegativity values are more likely to have negative oxidation states, while elements with lower electronegativity values are more likely to have positive oxidation states. Understanding this principle provides a deeper insight into the electronic structure and behavior of molecules.
Common Mistakes to Avoid
When determining oxidation states, there are a few common pitfalls that students often encounter. Avoiding these mistakes can help you arrive at the correct answer more consistently. One common mistake is forgetting the rules for elements like oxygen and hydrogen. Always remember that oxygen is usually -2 (except in peroxides and with fluorine) and hydrogen is usually +1 (except in metal hydrides). Another mistake is not accounting for the overall charge of an ion. If you're working with a polyatomic ion, make sure the sum of the oxidation states equals the charge of the ion, not zero.
Another frequent error is incorrectly assigning oxidation states based on assumptions rather than following the rules. For example, assuming that all elements in the same group have the same oxidation state in all compounds can lead to mistakes. It's important to consider the specific compound and apply the rules accordingly. Additionally, some students struggle with balancing the equation correctly, especially when dealing with more complex molecules or ions. Double-checking your work and ensuring that the sum of oxidation states matches the overall charge is crucial. By being mindful of these common mistakes and practicing regularly, you can improve your accuracy and confidence in determining oxidation states.
Practice Problems
Want to test your understanding? Here are a few practice problems to try out:
Answers:
Conclusion
So there you have it! Determining the oxidation state of phosphorus in PH3 is all about understanding the basic rules and applying them systematically. Remember that hydrogen usually has an oxidation state of +1, and the sum of oxidation states in a neutral molecule must be zero. By following these simple steps, you can confidently find the oxidation state of phosphorus in PH3 to be -3. Keep practicing, and you'll become a master of oxidation states in no time! Understanding these concepts not only helps in academic settings but also provides a solid foundation for comprehending more complex chemical reactions and compounds. Keep exploring and happy chemistry-ing!
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